Battery module cooling flow worksheet calculator

Calculate ideal mass flow and ideal volume flow with your own figures.

Your numbers

Use the units shown. Results update as you change valid inputs.

Use ideal mass flow and ideal volume flow to compare changes to your inputs. The method and limits below explain the scope.

Examples

Examples

Try the starting example

Heat to remove (W)
1000
Fluid specific heat (J/kg K)
4180
Allowed fluid temperature rise (K)
5
Fluid density (kg/m³)
1000
Ideal mass flow (kg/s)
0.047847
Ideal volume flow (litres/min)
2.870813

Try another scenario

Heat to remove (W)
1001
Fluid specific heat (J/kg K)
4180
Allowed fluid temperature rise (K)
5
Fluid density (kg/m³)
1000
Ideal mass flow (kg/s)
0.047895
Ideal volume flow (litres/min)
2.873684
Calculation method

Calculation method

Ideal mass flow (kg/s)

Ideal steady coolant m_dot=heat/(cp×temperature rise); divide by density for volume rate. No hydraulic/heat-exchanger sizing.

Ideal volume flow (litres/min)

Ideal steady coolant m_dot=heat/(cp×temperature rise); divide by density for volume rate. No hydraulic/heat-exchanger sizing.

Symbols and units
a
Heat to remove (W)
b
Fluid specific heat (J/kg K)
c
Allowed fluid temperature rise (K)
d
Fluid density (kg/m³)

Use the units shown. A list keeps the order in which you enter its values. The symbol ^ means “raised to the power of”.

Assumptions & limits

Assumptions & limits

  • User-supplied measurements and assumptions; Ideal steady coolant m_dot=heat/(cp×temperature rise); divide by density for volume rate. No hydraulic/heat-exchanger sizing. Supported limits: Finite numeric values bounded to 1e9 magnitude; lists and tables contain 1–100 records unless a stricter bound is stated. Inputs use the units shown. Lists explicitly paired by a method must have matching lengths; independent polynomial coefficient vectors may differ. Respect stated physical, interpolation, policy and computational domain limits.
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